ch10q6

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To->	e.V.	kcal/mol	cm^-1	sec^-1	erg
From e.V.	1	23.05	8.065 x 10³	2.43 x 10¹⁴	1.601 x 10^-12
From kcal/mol	4.345 x 10^-2	1	350	1.05 x 10¹³	6.95 x 10^-14
From cm^-1	1.24 x 10^-4	2.858 x 10^-3	1	3 x 10¹⁰(c)	1.986 x 10^-16(hc)
From sec^-1	4.13 x 10^-15	9.52 x 10^-14	3.33 x 10^-11	1	6.627 x 10^-27(hc)
From erg	6.25 x 10¹¹	1.439 x 10¹³	5.04 x 10¹⁵	1.51 x 10²⁶	1

e = 4.80286 x 10^-10 esu
m_e = 9.1055 x 10^-28gram
m_proton = 1.67312 x 10^-24 gram
h = 6.627 x 10^-27erg-sec
a_Bohr = 0.5296 x 10^-8cm
k_Boltzmann = 1.38033 x 10^-16ergs/K
c = 299793.3 km/sec

Calculate the time (in seconds) that it takes for an electron to completely circumnavigate the nucleus when the electron is in the n=24 orbit of a doubly positive Li cation.

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