e = 4.80286 x 10-10 e.s.u. me = 9.1055 x 10-28 gram mproton = 1.67312 x 10-24 gram h = 6.627 x 10-27 erg-sec aBohr = 0.5295 x 10-8 cm c = 299793.3 km/sec kBoltzmann = 1.38033 x 10-16 ergs/(moleculeoK) The visible lines in the Balmer series are due to H atoms undergoing transitions from n=2 to n=3, 4, 5, etc. (absorption). Calculate the shortest wavelength Balmer line (before the continuum) in Angstrom. (Use the reduced mass of the H atom.)
What's your answer? Choose your answer in scientific notation, i.e.,
+ - 1 2 3 4 5 6 7 8 9 . 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 E{ + - 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 }