ch10q00
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This document has been called 26 times.
To->
e.V.
kcal/mol
cm
-1
sec
-1
erg
From e.V.
1
23.05
8.065 x 10
3
2.43 x 10
14
1.601 x 10
-12
From kcal/mol
4.345 x 10
-2
1
350
1.05 x 10
13
6.95 x 10
-14
From cm
-1
1.24 x 10
-4
2.858 x 10
-3
1
3 x 10
10
(c)
1.986 x 10
-16
(hc)
From sec
-1
4.13 x 10
-15
9.52 x 10
-14
3.33 x 10
-11
1
6.627 x 10
-27
(hc)
From erg
6.25 x 10
11
1.439 x 10
13
5.04 x 10
15
1.51 x 10
26
1
e = 4.80286 x 10
-10
esu
m
e
= 9.1055 x 10
-28
gram
m
proton
= 1.67312 x 10
-24
gram
h = 6.627 x 10
-27
erg-sec
a
Bohr
= 0.5296 x 10
-8
cm
k
Boltzmann
= 1.38033 x 10
-16
ergs/K
c = 299793.3 km/sec
Data for the energy of emitted electrons as a function of incident wavelength is given:
253.6 nm; 1.95 e.V.
313.2 nm; 0.98 e.V.
365.0 nm; 0.50 e.V.
404.7 nm; 0.14 e.V.
Compute the slope between two of these points, and calculate the difference in that slope and Planck's constant. (Report your answer in erg-sec.)
Wavelength #1
253.6
313.2
365.0
404.7
Energy #1
1.95
0.98
0.50
0.14
Wavelength #2
253.6
313.2
365.0
404.7
Energy #2
1.95
0.98
0.50
0.14
Absolute value of difference between your slope and Planck's constant:
Query, is this answer correct?
/ time_stamp:14:37 ,Thursday, May 24, 20112
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